3.3.8 \(\int \frac {A+B \log (\frac {e (c+d x)^2}{(a+b x)^2})}{(a g+b g x)^4} \, dx\) [208]

3.3.8.1 Optimal result
3.3.8.2 Mathematica [A] (verified)
3.3.8.3 Rubi [A] (verified)
3.3.8.4 Maple [A] (verified)
3.3.8.5 Fricas [B] (verification not implemented)
3.3.8.6 Sympy [B] (verification not implemented)
3.3.8.7 Maxima [B] (verification not implemented)
3.3.8.8 Giac [B] (verification not implemented)
3.3.8.9 Mupad [B] (verification not implemented)

3.3.8.1 Optimal result

Integrand size = 32, antiderivative size = 177 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=\frac {2 B}{9 b g^4 (a+b x)^3}-\frac {B d}{3 b (b c-a d) g^4 (a+b x)^2}+\frac {2 B d^2}{3 b (b c-a d)^2 g^4 (a+b x)}+\frac {2 B d^3 \log (a+b x)}{3 b (b c-a d)^3 g^4}-\frac {2 B d^3 \log (c+d x)}{3 b (b c-a d)^3 g^4}-\frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{3 b g^4 (a+b x)^3} \]

output
2/9*B/b/g^4/(b*x+a)^3-1/3*B*d/b/(-a*d+b*c)/g^4/(b*x+a)^2+2/3*B*d^2/b/(-a*d 
+b*c)^2/g^4/(b*x+a)+2/3*B*d^3*ln(b*x+a)/b/(-a*d+b*c)^3/g^4-2/3*B*d^3*ln(d* 
x+c)/b/(-a*d+b*c)^3/g^4+1/3*(-A-B*ln(e*(d*x+c)^2/(b*x+a)^2))/b/g^4/(b*x+a) 
^3
 
3.3.8.2 Mathematica [A] (verified)

Time = 0.07 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.79 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=\frac {\frac {B \left (2 (b c-a d)^3-3 d (b c-a d)^2 (a+b x)+6 d^2 (b c-a d) (a+b x)^2+6 d^3 (a+b x)^3 \log (a+b x)-6 d^3 (a+b x)^3 \log (c+d x)\right )}{(b c-a d)^3}-3 \left (A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )\right )}{9 b g^4 (a+b x)^3} \]

input
Integrate[(A + B*Log[(e*(c + d*x)^2)/(a + b*x)^2])/(a*g + b*g*x)^4,x]
 
output
((B*(2*(b*c - a*d)^3 - 3*d*(b*c - a*d)^2*(a + b*x) + 6*d^2*(b*c - a*d)*(a 
+ b*x)^2 + 6*d^3*(a + b*x)^3*Log[a + b*x] - 6*d^3*(a + b*x)^3*Log[c + d*x] 
))/(b*c - a*d)^3 - 3*(A + B*Log[(e*(c + d*x)^2)/(a + b*x)^2]))/(9*b*g^4*(a 
 + b*x)^3)
 
3.3.8.3 Rubi [A] (verified)

Time = 0.33 (sec) , antiderivative size = 165, normalized size of antiderivative = 0.93, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {2948, 27, 54, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A}{(a g+b g x)^4} \, dx\)

\(\Big \downarrow \) 2948

\(\displaystyle -\frac {2 B (b c-a d) \int \frac {1}{g^3 (a+b x)^4 (c+d x)}dx}{3 b g}-\frac {B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A}{3 b g^4 (a+b x)^3}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {2 B (b c-a d) \int \frac {1}{(a+b x)^4 (c+d x)}dx}{3 b g^4}-\frac {B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A}{3 b g^4 (a+b x)^3}\)

\(\Big \downarrow \) 54

\(\displaystyle -\frac {2 B (b c-a d) \int \left (\frac {d^4}{(b c-a d)^4 (c+d x)}-\frac {b d^3}{(b c-a d)^4 (a+b x)}+\frac {b d^2}{(b c-a d)^3 (a+b x)^2}-\frac {b d}{(b c-a d)^2 (a+b x)^3}+\frac {b}{(b c-a d) (a+b x)^4}\right )dx}{3 b g^4}-\frac {B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A}{3 b g^4 (a+b x)^3}\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )+A}{3 b g^4 (a+b x)^3}-\frac {2 B (b c-a d) \left (-\frac {d^3 \log (a+b x)}{(b c-a d)^4}+\frac {d^3 \log (c+d x)}{(b c-a d)^4}-\frac {d^2}{(a+b x) (b c-a d)^3}+\frac {d}{2 (a+b x)^2 (b c-a d)^2}-\frac {1}{3 (a+b x)^3 (b c-a d)}\right )}{3 b g^4}\)

input
Int[(A + B*Log[(e*(c + d*x)^2)/(a + b*x)^2])/(a*g + b*g*x)^4,x]
 
output
(-2*B*(b*c - a*d)*(-1/3*1/((b*c - a*d)*(a + b*x)^3) + d/(2*(b*c - a*d)^2*( 
a + b*x)^2) - d^2/((b*c - a*d)^3*(a + b*x)) - (d^3*Log[a + b*x])/(b*c - a* 
d)^4 + (d^3*Log[c + d*x])/(b*c - a*d)^4))/(3*b*g^4) - (A + B*Log[(e*(c + d 
*x)^2)/(a + b*x)^2])/(3*b*g^4*(a + b*x)^3)
 

3.3.8.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 54
Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[E 
xpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && 
 ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && LtQ[m + n + 2, 0])
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2948
Int[((A_.) + Log[(e_.)*((a_.) + (b_.)*(x_))^(n_.)*((c_.) + (d_.)*(x_))^(mn_ 
)]*(B_.))*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(f + g*x)^(m + 1)*( 
(A + B*Log[e*((a + b*x)^n/(c + d*x)^n)])/(g*(m + 1))), x] - Simp[B*n*((b*c 
- a*d)/(g*(m + 1)))   Int[(f + g*x)^(m + 1)/((a + b*x)*(c + d*x)), x], x] / 
; FreeQ[{a, b, c, d, e, f, g, A, B, m, n}, x] && EqQ[n + mn, 0] && NeQ[b*c 
- a*d, 0] && NeQ[m, -1] &&  !(EqQ[m, -2] && IntegerQ[n])
 
3.3.8.4 Maple [A] (verified)

Time = 1.41 (sec) , antiderivative size = 211, normalized size of antiderivative = 1.19

method result size
derivativedivides \(-\frac {\frac {A}{3 g^{4} \left (b x +a \right )^{3}}+\frac {B \left (\frac {\ln \left (\frac {e \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )^{2}}{b^{2}}\right )}{3 \left (b x +a \right )^{3}}-\left (\frac {2 a d}{3}-\frac {2 c b}{3}\right ) \left (\frac {\frac {a^{2} d^{2}}{3 \left (b x +a \right )^{3}}-\frac {2 a b c d}{3 \left (b x +a \right )^{3}}+\frac {b^{2} c^{2}}{3 \left (b x +a \right )^{3}}+\frac {a \,d^{2}}{2 \left (b x +a \right )^{2}}-\frac {b c d}{2 \left (b x +a \right )^{2}}+\frac {d^{2}}{b x +a}}{\left (a d -c b \right )^{3}}+\frac {d^{3} \ln \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )}{\left (a d -c b \right )^{4}}\right )\right )}{g^{4}}}{b}\) \(211\)
default \(-\frac {\frac {A}{3 g^{4} \left (b x +a \right )^{3}}+\frac {B \left (\frac {\ln \left (\frac {e \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )^{2}}{b^{2}}\right )}{3 \left (b x +a \right )^{3}}-\left (\frac {2 a d}{3}-\frac {2 c b}{3}\right ) \left (\frac {\frac {a^{2} d^{2}}{3 \left (b x +a \right )^{3}}-\frac {2 a b c d}{3 \left (b x +a \right )^{3}}+\frac {b^{2} c^{2}}{3 \left (b x +a \right )^{3}}+\frac {a \,d^{2}}{2 \left (b x +a \right )^{2}}-\frac {b c d}{2 \left (b x +a \right )^{2}}+\frac {d^{2}}{b x +a}}{\left (a d -c b \right )^{3}}+\frac {d^{3} \ln \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )}{\left (a d -c b \right )^{4}}\right )\right )}{g^{4}}}{b}\) \(211\)
parts \(-\frac {A}{3 g^{4} \left (b x +a \right )^{3} b}-\frac {B \left (\frac {\ln \left (\frac {e \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )^{2}}{b^{2}}\right )}{3 \left (b x +a \right )^{3}}-\left (\frac {2 a d}{3}-\frac {2 c b}{3}\right ) \left (\frac {\frac {a^{2} d^{2}}{3 \left (b x +a \right )^{3}}-\frac {2 a b c d}{3 \left (b x +a \right )^{3}}+\frac {b^{2} c^{2}}{3 \left (b x +a \right )^{3}}+\frac {a \,d^{2}}{2 \left (b x +a \right )^{2}}-\frac {b c d}{2 \left (b x +a \right )^{2}}+\frac {d^{2}}{b x +a}}{\left (a d -c b \right )^{3}}+\frac {d^{3} \ln \left (\frac {a d}{b x +a}-\frac {b c}{b x +a}-d \right )}{\left (a d -c b \right )^{4}}\right )\right )}{g^{4} b}\) \(213\)
risch \(-\frac {B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right )}{3 b \,g^{4} \left (b x +a \right )^{3}}-\frac {-6 B \ln \left (-d x -c \right ) b^{3} d^{3} x^{3}+6 B \ln \left (b x +a \right ) b^{3} d^{3} x^{3}-18 B \ln \left (-d x -c \right ) a \,b^{2} d^{3} x^{2}+18 B \ln \left (b x +a \right ) a \,b^{2} d^{3} x^{2}-18 B \ln \left (-d x -c \right ) a^{2} b \,d^{3} x +18 B \ln \left (b x +a \right ) a^{2} b \,d^{3} x -6 B a \,b^{2} d^{3} x^{2}+6 B \,b^{3} c \,d^{2} x^{2}-6 B \ln \left (-d x -c \right ) a^{3} d^{3}+6 B \ln \left (b x +a \right ) a^{3} d^{3}-15 B \,a^{2} b \,d^{3} x +18 B a \,b^{2} c \,d^{2} x -3 B \,b^{3} c^{2} d x +3 A \,a^{3} d^{3}-9 A \,a^{2} b c \,d^{2}+9 A a \,b^{2} c^{2} d -3 A \,b^{3} c^{3}-11 B \,a^{3} d^{3}+18 B \,a^{2} b c \,d^{2}-9 B a \,b^{2} c^{2} d +2 B \,c^{3} b^{3}}{9 \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right ) g^{4} \left (b x +a \right )^{3} b}\) \(379\)
parallelrisch \(-\frac {-18 A \,a^{2} b^{5} c \,d^{3}+18 A a \,b^{6} c^{2} d^{2}-18 B \,x^{2} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a \,b^{6} d^{4}-18 B x \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{2} b^{5} d^{4}-18 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a^{2} b^{5} c \,d^{3}+18 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) a \,b^{6} c^{2} d^{2}+36 B x a \,b^{6} c \,d^{3}-30 B x \,a^{2} b^{5} d^{4}-6 B x \,b^{7} c^{2} d^{2}-12 B \,x^{2} a \,b^{6} d^{4}+12 B \,x^{2} b^{7} c \,d^{3}+6 A \,a^{3} b^{4} d^{4}-6 A \,b^{7} c^{3} d -22 B \,a^{3} b^{4} d^{4}+4 B \,b^{7} c^{3} d -6 B \,x^{3} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) b^{7} d^{4}-6 B \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right ) b^{7} c^{3} d +36 B \,a^{2} b^{5} c \,d^{3}-18 B a \,b^{6} c^{2} d^{2}}{18 g^{4} \left (b x +a \right )^{3} \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right ) b^{5} d}\) \(394\)
norman \(\frac {\frac {B \,a^{2} d^{3} x \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right )}{\left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right ) g}+\frac {B a b \,d^{3} x^{2} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right )}{\left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right ) g}+\frac {\left (3 A \,a^{2} d^{2}-6 A a b c d +3 A \,b^{2} c^{2}-6 B \,a^{2} d^{2}+6 B a b c d -2 B \,b^{2} c^{2}\right ) x}{3 g a \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {B c \left (3 a^{2} d^{2}-3 a b c d +b^{2} c^{2}\right ) \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right )}{3 g \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right )}+\frac {\left (3 A \,a^{2} d^{2}-6 A a b c d +3 A \,b^{2} c^{2}-11 B \,a^{2} d^{2}+7 B a b c d -2 B \,b^{2} c^{2}\right ) b^{2} x^{3}}{9 a^{3} g \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {\left (3 A \,a^{2} d^{2}-6 A a b c d +3 A \,b^{2} c^{2}-9 B \,a^{2} d^{2}+7 B a b c d -2 B \,b^{2} c^{2}\right ) b \,x^{2}}{3 g \,a^{2} \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {B \,b^{2} d^{3} x^{3} \ln \left (\frac {e \left (d x +c \right )^{2}}{\left (b x +a \right )^{2}}\right )}{3 \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right ) g}}{g^{3} \left (b x +a \right )^{3}}\) \(559\)

input
int((A+B*ln(e*(d*x+c)^2/(b*x+a)^2))/(b*g*x+a*g)^4,x,method=_RETURNVERBOSE)
 
output
-1/b*(1/3/g^4*A/(b*x+a)^3+1/g^4*B*(1/3/(b*x+a)^3*ln(e*(a*d/(b*x+a)-b*c/(b* 
x+a)-d)^2/b^2)-(2/3*a*d-2/3*c*b)*(1/(a*d-b*c)^3*(1/3*a^2*d^2/(b*x+a)^3-2/3 
*a*b*c*d/(b*x+a)^3+1/3*b^2*c^2/(b*x+a)^3+1/2*a*d^2/(b*x+a)^2-1/2*b*c*d/(b* 
x+a)^2+d^2/(b*x+a))+d^3/(a*d-b*c)^4*ln(a*d/(b*x+a)-b*c/(b*x+a)-d))))
 
3.3.8.5 Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 432 vs. \(2 (165) = 330\).

Time = 0.28 (sec) , antiderivative size = 432, normalized size of antiderivative = 2.44 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=-\frac {{\left (3 \, A - 2 \, B\right )} b^{3} c^{3} - 9 \, {\left (A - B\right )} a b^{2} c^{2} d + 9 \, {\left (A - 2 \, B\right )} a^{2} b c d^{2} - {\left (3 \, A - 11 \, B\right )} a^{3} d^{3} - 6 \, {\left (B b^{3} c d^{2} - B a b^{2} d^{3}\right )} x^{2} + 3 \, {\left (B b^{3} c^{2} d - 6 \, B a b^{2} c d^{2} + 5 \, B a^{2} b d^{3}\right )} x + 3 \, {\left (B b^{3} d^{3} x^{3} + 3 \, B a b^{2} d^{3} x^{2} + 3 \, B a^{2} b d^{3} x + B b^{3} c^{3} - 3 \, B a b^{2} c^{2} d + 3 \, B a^{2} b c d^{2}\right )} \log \left (\frac {d^{2} e x^{2} + 2 \, c d e x + c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right )}{9 \, {\left ({\left (b^{7} c^{3} - 3 \, a b^{6} c^{2} d + 3 \, a^{2} b^{5} c d^{2} - a^{3} b^{4} d^{3}\right )} g^{4} x^{3} + 3 \, {\left (a b^{6} c^{3} - 3 \, a^{2} b^{5} c^{2} d + 3 \, a^{3} b^{4} c d^{2} - a^{4} b^{3} d^{3}\right )} g^{4} x^{2} + 3 \, {\left (a^{2} b^{5} c^{3} - 3 \, a^{3} b^{4} c^{2} d + 3 \, a^{4} b^{3} c d^{2} - a^{5} b^{2} d^{3}\right )} g^{4} x + {\left (a^{3} b^{4} c^{3} - 3 \, a^{4} b^{3} c^{2} d + 3 \, a^{5} b^{2} c d^{2} - a^{6} b d^{3}\right )} g^{4}\right )}} \]

input
integrate((A+B*log(e*(d*x+c)^2/(b*x+a)^2))/(b*g*x+a*g)^4,x, algorithm="fri 
cas")
 
output
-1/9*((3*A - 2*B)*b^3*c^3 - 9*(A - B)*a*b^2*c^2*d + 9*(A - 2*B)*a^2*b*c*d^ 
2 - (3*A - 11*B)*a^3*d^3 - 6*(B*b^3*c*d^2 - B*a*b^2*d^3)*x^2 + 3*(B*b^3*c^ 
2*d - 6*B*a*b^2*c*d^2 + 5*B*a^2*b*d^3)*x + 3*(B*b^3*d^3*x^3 + 3*B*a*b^2*d^ 
3*x^2 + 3*B*a^2*b*d^3*x + B*b^3*c^3 - 3*B*a*b^2*c^2*d + 3*B*a^2*b*c*d^2)*l 
og((d^2*e*x^2 + 2*c*d*e*x + c^2*e)/(b^2*x^2 + 2*a*b*x + a^2)))/((b^7*c^3 - 
 3*a*b^6*c^2*d + 3*a^2*b^5*c*d^2 - a^3*b^4*d^3)*g^4*x^3 + 3*(a*b^6*c^3 - 3 
*a^2*b^5*c^2*d + 3*a^3*b^4*c*d^2 - a^4*b^3*d^3)*g^4*x^2 + 3*(a^2*b^5*c^3 - 
 3*a^3*b^4*c^2*d + 3*a^4*b^3*c*d^2 - a^5*b^2*d^3)*g^4*x + (a^3*b^4*c^3 - 3 
*a^4*b^3*c^2*d + 3*a^5*b^2*c*d^2 - a^6*b*d^3)*g^4)
 
3.3.8.6 Sympy [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 677 vs. \(2 (162) = 324\).

Time = 1.78 (sec) , antiderivative size = 677, normalized size of antiderivative = 3.82 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=- \frac {B \log {\left (\frac {e \left (c + d x\right )^{2}}{\left (a + b x\right )^{2}} \right )}}{3 a^{3} b g^{4} + 9 a^{2} b^{2} g^{4} x + 9 a b^{3} g^{4} x^{2} + 3 b^{4} g^{4} x^{3}} + \frac {2 B d^{3} \log {\left (x + \frac {- \frac {2 B a^{4} d^{7}}{\left (a d - b c\right )^{3}} + \frac {8 B a^{3} b c d^{6}}{\left (a d - b c\right )^{3}} - \frac {12 B a^{2} b^{2} c^{2} d^{5}}{\left (a d - b c\right )^{3}} + \frac {8 B a b^{3} c^{3} d^{4}}{\left (a d - b c\right )^{3}} + 2 B a d^{4} - \frac {2 B b^{4} c^{4} d^{3}}{\left (a d - b c\right )^{3}} + 2 B b c d^{3}}{4 B b d^{4}} \right )}}{3 b g^{4} \left (a d - b c\right )^{3}} - \frac {2 B d^{3} \log {\left (x + \frac {\frac {2 B a^{4} d^{7}}{\left (a d - b c\right )^{3}} - \frac {8 B a^{3} b c d^{6}}{\left (a d - b c\right )^{3}} + \frac {12 B a^{2} b^{2} c^{2} d^{5}}{\left (a d - b c\right )^{3}} - \frac {8 B a b^{3} c^{3} d^{4}}{\left (a d - b c\right )^{3}} + 2 B a d^{4} + \frac {2 B b^{4} c^{4} d^{3}}{\left (a d - b c\right )^{3}} + 2 B b c d^{3}}{4 B b d^{4}} \right )}}{3 b g^{4} \left (a d - b c\right )^{3}} + \frac {- 3 A a^{2} d^{2} + 6 A a b c d - 3 A b^{2} c^{2} + 11 B a^{2} d^{2} - 7 B a b c d + 2 B b^{2} c^{2} + 6 B b^{2} d^{2} x^{2} + x \left (15 B a b d^{2} - 3 B b^{2} c d\right )}{9 a^{5} b d^{2} g^{4} - 18 a^{4} b^{2} c d g^{4} + 9 a^{3} b^{3} c^{2} g^{4} + x^{3} \cdot \left (9 a^{2} b^{4} d^{2} g^{4} - 18 a b^{5} c d g^{4} + 9 b^{6} c^{2} g^{4}\right ) + x^{2} \cdot \left (27 a^{3} b^{3} d^{2} g^{4} - 54 a^{2} b^{4} c d g^{4} + 27 a b^{5} c^{2} g^{4}\right ) + x \left (27 a^{4} b^{2} d^{2} g^{4} - 54 a^{3} b^{3} c d g^{4} + 27 a^{2} b^{4} c^{2} g^{4}\right )} \]

input
integrate((A+B*ln(e*(d*x+c)**2/(b*x+a)**2))/(b*g*x+a*g)**4,x)
 
output
-B*log(e*(c + d*x)**2/(a + b*x)**2)/(3*a**3*b*g**4 + 9*a**2*b**2*g**4*x + 
9*a*b**3*g**4*x**2 + 3*b**4*g**4*x**3) + 2*B*d**3*log(x + (-2*B*a**4*d**7/ 
(a*d - b*c)**3 + 8*B*a**3*b*c*d**6/(a*d - b*c)**3 - 12*B*a**2*b**2*c**2*d* 
*5/(a*d - b*c)**3 + 8*B*a*b**3*c**3*d**4/(a*d - b*c)**3 + 2*B*a*d**4 - 2*B 
*b**4*c**4*d**3/(a*d - b*c)**3 + 2*B*b*c*d**3)/(4*B*b*d**4))/(3*b*g**4*(a* 
d - b*c)**3) - 2*B*d**3*log(x + (2*B*a**4*d**7/(a*d - b*c)**3 - 8*B*a**3*b 
*c*d**6/(a*d - b*c)**3 + 12*B*a**2*b**2*c**2*d**5/(a*d - b*c)**3 - 8*B*a*b 
**3*c**3*d**4/(a*d - b*c)**3 + 2*B*a*d**4 + 2*B*b**4*c**4*d**3/(a*d - b*c) 
**3 + 2*B*b*c*d**3)/(4*B*b*d**4))/(3*b*g**4*(a*d - b*c)**3) + (-3*A*a**2*d 
**2 + 6*A*a*b*c*d - 3*A*b**2*c**2 + 11*B*a**2*d**2 - 7*B*a*b*c*d + 2*B*b** 
2*c**2 + 6*B*b**2*d**2*x**2 + x*(15*B*a*b*d**2 - 3*B*b**2*c*d))/(9*a**5*b* 
d**2*g**4 - 18*a**4*b**2*c*d*g**4 + 9*a**3*b**3*c**2*g**4 + x**3*(9*a**2*b 
**4*d**2*g**4 - 18*a*b**5*c*d*g**4 + 9*b**6*c**2*g**4) + x**2*(27*a**3*b** 
3*d**2*g**4 - 54*a**2*b**4*c*d*g**4 + 27*a*b**5*c**2*g**4) + x*(27*a**4*b* 
*2*d**2*g**4 - 54*a**3*b**3*c*d*g**4 + 27*a**2*b**4*c**2*g**4))
 
3.3.8.7 Maxima [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 480 vs. \(2 (165) = 330\).

Time = 0.22 (sec) , antiderivative size = 480, normalized size of antiderivative = 2.71 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=\frac {1}{9} \, B {\left (\frac {6 \, b^{2} d^{2} x^{2} + 2 \, b^{2} c^{2} - 7 \, a b c d + 11 \, a^{2} d^{2} - 3 \, {\left (b^{2} c d - 5 \, a b d^{2}\right )} x}{{\left (b^{6} c^{2} - 2 \, a b^{5} c d + a^{2} b^{4} d^{2}\right )} g^{4} x^{3} + 3 \, {\left (a b^{5} c^{2} - 2 \, a^{2} b^{4} c d + a^{3} b^{3} d^{2}\right )} g^{4} x^{2} + 3 \, {\left (a^{2} b^{4} c^{2} - 2 \, a^{3} b^{3} c d + a^{4} b^{2} d^{2}\right )} g^{4} x + {\left (a^{3} b^{3} c^{2} - 2 \, a^{4} b^{2} c d + a^{5} b d^{2}\right )} g^{4}} - \frac {3 \, \log \left (\frac {d^{2} e x^{2}}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {2 \, c d e x}{b^{2} x^{2} + 2 \, a b x + a^{2}} + \frac {c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right )}{b^{4} g^{4} x^{3} + 3 \, a b^{3} g^{4} x^{2} + 3 \, a^{2} b^{2} g^{4} x + a^{3} b g^{4}} + \frac {6 \, d^{3} \log \left (b x + a\right )}{{\left (b^{4} c^{3} - 3 \, a b^{3} c^{2} d + 3 \, a^{2} b^{2} c d^{2} - a^{3} b d^{3}\right )} g^{4}} - \frac {6 \, d^{3} \log \left (d x + c\right )}{{\left (b^{4} c^{3} - 3 \, a b^{3} c^{2} d + 3 \, a^{2} b^{2} c d^{2} - a^{3} b d^{3}\right )} g^{4}}\right )} - \frac {A}{3 \, {\left (b^{4} g^{4} x^{3} + 3 \, a b^{3} g^{4} x^{2} + 3 \, a^{2} b^{2} g^{4} x + a^{3} b g^{4}\right )}} \]

input
integrate((A+B*log(e*(d*x+c)^2/(b*x+a)^2))/(b*g*x+a*g)^4,x, algorithm="max 
ima")
 
output
1/9*B*((6*b^2*d^2*x^2 + 2*b^2*c^2 - 7*a*b*c*d + 11*a^2*d^2 - 3*(b^2*c*d - 
5*a*b*d^2)*x)/((b^6*c^2 - 2*a*b^5*c*d + a^2*b^4*d^2)*g^4*x^3 + 3*(a*b^5*c^ 
2 - 2*a^2*b^4*c*d + a^3*b^3*d^2)*g^4*x^2 + 3*(a^2*b^4*c^2 - 2*a^3*b^3*c*d 
+ a^4*b^2*d^2)*g^4*x + (a^3*b^3*c^2 - 2*a^4*b^2*c*d + a^5*b*d^2)*g^4) - 3* 
log(d^2*e*x^2/(b^2*x^2 + 2*a*b*x + a^2) + 2*c*d*e*x/(b^2*x^2 + 2*a*b*x + a 
^2) + c^2*e/(b^2*x^2 + 2*a*b*x + a^2))/(b^4*g^4*x^3 + 3*a*b^3*g^4*x^2 + 3* 
a^2*b^2*g^4*x + a^3*b*g^4) + 6*d^3*log(b*x + a)/((b^4*c^3 - 3*a*b^3*c^2*d 
+ 3*a^2*b^2*c*d^2 - a^3*b*d^3)*g^4) - 6*d^3*log(d*x + c)/((b^4*c^3 - 3*a*b 
^3*c^2*d + 3*a^2*b^2*c*d^2 - a^3*b*d^3)*g^4)) - 1/3*A/(b^4*g^4*x^3 + 3*a*b 
^3*g^4*x^2 + 3*a^2*b^2*g^4*x + a^3*b*g^4)
 
3.3.8.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 477 vs. \(2 (165) = 330\).

Time = 0.38 (sec) , antiderivative size = 477, normalized size of antiderivative = 2.69 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=\frac {2 \, B d^{3} \log \left (b x + a\right )}{3 \, {\left (b^{4} c^{3} g^{4} - 3 \, a b^{3} c^{2} d g^{4} + 3 \, a^{2} b^{2} c d^{2} g^{4} - a^{3} b d^{3} g^{4}\right )}} - \frac {2 \, B d^{3} \log \left (d x + c\right )}{3 \, {\left (b^{4} c^{3} g^{4} - 3 \, a b^{3} c^{2} d g^{4} + 3 \, a^{2} b^{2} c d^{2} g^{4} - a^{3} b d^{3} g^{4}\right )}} - \frac {B \log \left (\frac {d^{2} e x^{2} + 2 \, c d e x + c^{2} e}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right )}{3 \, {\left (b^{4} g^{4} x^{3} + 3 \, a b^{3} g^{4} x^{2} + 3 \, a^{2} b^{2} g^{4} x + a^{3} b g^{4}\right )}} + \frac {6 \, B b^{2} d^{2} x^{2} - 3 \, B b^{2} c d x + 15 \, B a b d^{2} x - 3 \, A b^{2} c^{2} + 2 \, B b^{2} c^{2} + 6 \, A a b c d - 7 \, B a b c d - 3 \, A a^{2} d^{2} + 11 \, B a^{2} d^{2}}{9 \, {\left (b^{6} c^{2} g^{4} x^{3} - 2 \, a b^{5} c d g^{4} x^{3} + a^{2} b^{4} d^{2} g^{4} x^{3} + 3 \, a b^{5} c^{2} g^{4} x^{2} - 6 \, a^{2} b^{4} c d g^{4} x^{2} + 3 \, a^{3} b^{3} d^{2} g^{4} x^{2} + 3 \, a^{2} b^{4} c^{2} g^{4} x - 6 \, a^{3} b^{3} c d g^{4} x + 3 \, a^{4} b^{2} d^{2} g^{4} x + a^{3} b^{3} c^{2} g^{4} - 2 \, a^{4} b^{2} c d g^{4} + a^{5} b d^{2} g^{4}\right )}} \]

input
integrate((A+B*log(e*(d*x+c)^2/(b*x+a)^2))/(b*g*x+a*g)^4,x, algorithm="gia 
c")
 
output
2/3*B*d^3*log(b*x + a)/(b^4*c^3*g^4 - 3*a*b^3*c^2*d*g^4 + 3*a^2*b^2*c*d^2* 
g^4 - a^3*b*d^3*g^4) - 2/3*B*d^3*log(d*x + c)/(b^4*c^3*g^4 - 3*a*b^3*c^2*d 
*g^4 + 3*a^2*b^2*c*d^2*g^4 - a^3*b*d^3*g^4) - 1/3*B*log((d^2*e*x^2 + 2*c*d 
*e*x + c^2*e)/(b^2*x^2 + 2*a*b*x + a^2))/(b^4*g^4*x^3 + 3*a*b^3*g^4*x^2 + 
3*a^2*b^2*g^4*x + a^3*b*g^4) + 1/9*(6*B*b^2*d^2*x^2 - 3*B*b^2*c*d*x + 15*B 
*a*b*d^2*x - 3*A*b^2*c^2 + 2*B*b^2*c^2 + 6*A*a*b*c*d - 7*B*a*b*c*d - 3*A*a 
^2*d^2 + 11*B*a^2*d^2)/(b^6*c^2*g^4*x^3 - 2*a*b^5*c*d*g^4*x^3 + a^2*b^4*d^ 
2*g^4*x^3 + 3*a*b^5*c^2*g^4*x^2 - 6*a^2*b^4*c*d*g^4*x^2 + 3*a^3*b^3*d^2*g^ 
4*x^2 + 3*a^2*b^4*c^2*g^4*x - 6*a^3*b^3*c*d*g^4*x + 3*a^4*b^2*d^2*g^4*x + 
a^3*b^3*c^2*g^4 - 2*a^4*b^2*c*d*g^4 + a^5*b*d^2*g^4)
 
3.3.8.9 Mupad [B] (verification not implemented)

Time = 3.31 (sec) , antiderivative size = 341, normalized size of antiderivative = 1.93 \[ \int \frac {A+B \log \left (\frac {e (c+d x)^2}{(a+b x)^2}\right )}{(a g+b g x)^4} \, dx=\frac {2\,B\,b\,c^2}{9\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}-\frac {A\,b\,c^2}{3\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}-\frac {B\,\ln \left (\frac {e\,{\left (c+d\,x\right )}^2}{{\left (a+b\,x\right )}^2}\right )}{3\,b\,g^4\,{\left (a+b\,x\right )}^3}-\frac {A\,a^2\,d^2}{3\,b\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}+\frac {11\,B\,a^2\,d^2}{9\,b\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}+\frac {5\,B\,a\,d^2\,x}{3\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}+\frac {2\,B\,b\,d^2\,x^2}{3\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}+\frac {2\,A\,a\,c\,d}{3\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}-\frac {7\,B\,a\,c\,d}{9\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}-\frac {B\,b\,c\,d\,x}{3\,g^4\,{\left (a\,d-b\,c\right )}^2\,{\left (a+b\,x\right )}^3}+\frac {B\,d^3\,\mathrm {atan}\left (\frac {a\,d\,1{}\mathrm {i}+b\,c\,1{}\mathrm {i}+b\,d\,x\,2{}\mathrm {i}}{a\,d-b\,c}\right )\,4{}\mathrm {i}}{3\,b\,g^4\,{\left (a\,d-b\,c\right )}^3} \]

input
int((A + B*log((e*(c + d*x)^2)/(a + b*x)^2))/(a*g + b*g*x)^4,x)
 
output
(B*d^3*atan((a*d*1i + b*c*1i + b*d*x*2i)/(a*d - b*c))*4i)/(3*b*g^4*(a*d - 
b*c)^3) - (B*log((e*(c + d*x)^2)/(a + b*x)^2))/(3*b*g^4*(a + b*x)^3) - (A* 
b*c^2)/(3*g^4*(a*d - b*c)^2*(a + b*x)^3) + (2*B*b*c^2)/(9*g^4*(a*d - b*c)^ 
2*(a + b*x)^3) - (A*a^2*d^2)/(3*b*g^4*(a*d - b*c)^2*(a + b*x)^3) + (11*B*a 
^2*d^2)/(9*b*g^4*(a*d - b*c)^2*(a + b*x)^3) + (5*B*a*d^2*x)/(3*g^4*(a*d - 
b*c)^2*(a + b*x)^3) + (2*B*b*d^2*x^2)/(3*g^4*(a*d - b*c)^2*(a + b*x)^3) + 
(2*A*a*c*d)/(3*g^4*(a*d - b*c)^2*(a + b*x)^3) - (7*B*a*c*d)/(9*g^4*(a*d - 
b*c)^2*(a + b*x)^3) - (B*b*c*d*x)/(3*g^4*(a*d - b*c)^2*(a + b*x)^3)